custom Switch button in footer
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there's no need to change which rows should be displayed or not, because I manage this myself in the homepage (which is also the footer). when here, for example, you're on an Artwork detail page, you need to be able to display the correct corresponding category in the footer as if you'd clicked on it (as on the homepage).
in your previous code, the category selection worked but not the simulated click to display the correct category (artwork or series). As I said earlier in my messages. Is this more understandable ?
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as i said i need a simpler test case
:(
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to answer your question from the ‘anchor conflict’ topic, no, unfortunately that didn't solve the problem, which I'm still trying to resolve. I've re-applied the code you gave me here above but same thing, it displays the correct Serie/Artworks switch button corresponding to the page's cat-id, but it doesn't display the content accordingly (as if Artworks had actually been clicked).
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ok. if you could create a page where you just have like 2 or 3 rows in there. and make the bug happen in this simpler case.
then i can try and fix it. cause this example case is too complex. -
I've made a test page with the same footer operation, let me know if this is better for you: https://benoitlefeuvre.com/test/
thanks!
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hi
up 🧌 -
hey oh yea i need to check this out sry
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in this case, the switch button should be on Artworks, as the page category is data-catid=“[3]” and should display the correct content as if Artworks had been clicked.
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im checking it out now
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ok it seems like i had a really hard time to understand what the problem was :O
i misunderstood youbasically you just need to trigger a click on one of the buttons
u got two buttons:
.artworks-button
and
.overview-button
and as far as i understand this would be the way to do it:
when you go to a page where you want overview-button to be auto-activated:
window.laytheme.on('newpageshown', function(){ if(jQuery("body").hasClass("slug-home"){ jQuery(".overview-button").click(); } })
basically when you visit the homepage, this will click the overview button using javascript:
but maybe u need to remove this custom js u got here:
this could be in conflict with that click js
i think u just add "selected" classmaybe for styling, instead use the class "expand-link-clicked" cause thats the "active" class
so basically with newpageshown and checking the body class you can find out which page u just landed on.
and then either calljQuery(".overview-button").click();
or
jQuery(".artworks-button").click();
if my previous code was checking the right pages (no idea), it could for example look like
window.laytheme.on('newpageshown', function(){ if(jQuery('body').attr('data-catid') == '[3]'){ jQuery(".artworks-button").click(); } else if(jQuery('body').attr('data-catid') == '[1]'){ jQuery(".overview-button").click(); } })
but basically this was no lay theme bug, you just needed help with your custom code
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Thanks for your reply. You're right, it's probably not a Lay bug but rather that I need help with my code. I tested it, but unfortunately it doesn't work.
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:/
can you tell me:
which page should have what button activated??and can u gimme your /wp-admin/ login
can you send your website address, /wp-admin/ username and password and a link to this topic to info@laytheme.com?
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<script> window.laytheme.on('newpageshown', function(){ setTimeout(function(){ if(jQuery('body').attr('data-catid') == '[3]'){ if( window.utility.isDesktopOrTabletSize ) { jQuery("#footer .artworks-button").click().addClass("selected"); jQuery("#footer .overview-button").removeClass("selected"); } else { jQuery("#footer-custom-phone-grid .artworks-button").click().addClass("selected"); jQuery("#footer-custom-phone-grid .overview-button").removeClass("selected"); } } else if(jQuery('body').attr('data-catid') == '[1]'){ if( window.utility.isDesktopOrTabletSize ) { jQuery("#footer .overview-button").click().addClass("selected"); jQuery("#footer .artworks-button").removeClass("selected"); } else { jQuery("#footer-custom-phone-grid .overview-button").click().addClass("selected"); jQuery("#footer-custom-phone-grid .artworks-button").removeClass("selected"); } } }, 1000) }) </script>
seems like this code is what was needed
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Thank you very much for your help and your time. That's exactly what I was looking for 🙏
I also code custom websites or custom Lay features.
💿 Email me here: 💿
info@laytheme.com
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