I will have to check that slug/type situation to be sure to have a clean and functional website in the future… But in the meantime the code you sent works perfectly! Thank you very much! :)

Best wishes,

@TYLM

Unsure why myself (could be your product page?), but regardless you can still use this information to apply jQuery:

<script>
window.laytheme.on("newpageshown", function(layoutObj, type, obj){

	if(type == "archive" && obj.id == 553){
		console.log("fantastic!");
	}
});
</script>

Best wishes ✨

Richard

I don't know why but my shop page is not a page but an archive – it's not supposed to be tho. I applied the code to have the console readout and I get this :

obj 
Object { id: "553", type: "archive", slug: "product", catid: "" }
catid: ""
id: "553"
slug: "product"
type: "archive"
<prototype>: Object { … }

That's probably why I can't use the if statement correctly.
It's weird that the slug here is "product" when the actual slug is "shop"…
And I really don't understand that “Archive” thing.

@TYLM

My main shop page is a page is your's not?
When applying the following code (documentation):

<script>
window.laytheme.on("newpageshown", function(layoutObj, type, obj){
	console.log("layoutObj", layoutObj);
	console.log("type", type);
	console.log("obj", obj);
});
</script>

I get a console readout:

obj 
{id: '11', type: 'page', slug: 'shop', catid: ''}
catid: ""
id: "11"
slug: "shop"
type: "page"
[[Prototype]]: Object

Then i can use the following if statement to be sure:

<script>
window.laytheme.on("newpageshown", function(layoutObj, type, obj){

	if(type == "page" && obj.id == 11){
		console.log("fantastic!");
	}
});
</script>

Result:

So i know the code that i use within the if statement will be applied to this page.

Hope this helps & best wishes Théo ✨

Richard